19/-16y^-4

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Solution for 19/-16y^-4 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

(19/(-16))*y^-4 = 0

-19/16*y^-4 = 0 // : -19/16

y^-4 = 0

y należy do O

y belongs to the empty set

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